(x^2+y^2)(x^2+y^2)=32

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Solution for (x^2+y^2)(x^2+y^2)=32 equation:


Simplifying
(x2 + y2)(x2 + y2) = 32

Multiply (x2 + y2) * (x2 + y2)
(x2(x2 + y2) + y2(x2 + y2)) = 32
((x2 * x2 + y2 * x2) + y2(x2 + y2)) = 32

Reorder the terms:
((x2y2 + x4) + y2(x2 + y2)) = 32
((x2y2 + x4) + y2(x2 + y2)) = 32
(x2y2 + x4 + (x2 * y2 + y2 * y2)) = 32
(x2y2 + x4 + (x2y2 + y4)) = 32

Reorder the terms:
(x2y2 + x2y2 + x4 + y4) = 32

Combine like terms: x2y2 + x2y2 = 2x2y2
(2x2y2 + x4 + y4) = 32

Solving
2x2y2 + x4 + y4 = 32

Solving for variable 'x'.

Reorder the terms:
-32 + 2x2y2 + x4 + y4 = 32 + -32

Combine like terms: 32 + -32 = 0
-32 + 2x2y2 + x4 + y4 = 0

The solution to this equation could not be determined.

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